How it works
Estimate sensible heat with constant specific heat capacity and no phase change. A temperature difference in kelvin equals one in Celsius.
Inputs and units
| Input | Example value | What to enter |
|---|---|---|
| Mass | 1 kg | Required unit: kg. Use a non-negative value. |
| Specific heat capacity | 4,184 J/(kg·K) | Required unit: J/(kg·K). Must be greater than zero. |
| Temperature change | 20 K | Required unit: K. |
Worked example
Show example inputs and results
This example is generated by the same calculation engine using the starting values in the form. Your own inputs produce your own result.
- Mass
- 1 kg
- Specific heat capacity
- 4,184 J/(kg·K)
- Temperature change
- 20 K
Complete example results
- Heat transferred
- 83,680 J
Reading the result
Check the units used in the formula together. The result follows the stated ideal model and supplied constants; material, environment and losses are included only where the inputs or method explicitly define them.
Questions and answers
Can I use the example values for my own calculation?
The example values illustrate the calculation. Replace every input with your own information, especially dates, rates and the selected operation.
Why are some results rounded?
Results display up to 8 decimal places. Calculations use the unrounded values; very small values use scientific notation. JavaScript floating-point arithmetic can introduce tiny rounding differences.
Are my inputs sent to a server?
The calculator processes inputs in your browser. Its code does not send your values to a server.